What is the difference between compton scattering and photoelectric effect

The Coulomb constant, the electric force constant, or the electrostatic constant denoted ke, k or K is a proportionality constant in electrostatics equations. In SI units it is equal to 8. Begin typing your search term above and press enter to search. Press ESC to cancel. Skip to content Home Philosophy What is the difference between photoelectric effect and Compton effect?

Ben Davis September 23, What is the difference between photoelectric effect and Compton effect? What is called Compton effect? What is meant by Compton effect? This is the main difference between Photoelectric Effect and Compton Effect. The photoelectric effect is an effect where weakly bound electrons within metals are ejected from the material when electromagnetic radiation interacts with those electrons. The ejected electrons are known as the photoelectrons. There are several important experimental observations relevant to the photoelectric effect.

Some of them are;. The classical theory of electromagnetism cannot explain the above experimental observations except the fourth observation. So, Albert Einstein developed a revolutionary theory to explain the photoelectric effect. He used the quantization idea of the electromagnetic radiation in his theory.

According to his theory, light consists of energy packets or energy quanta called photons. They are absorbed or produced as units of energy packets. Simply, fractional energy packets do not exist.

His theory suggests that the energy of a photon is completely acquired by a single electron in the metal. The electron spends a certain amount of energy work function of the material to liberate from its binding in the material.

The electron comes out from the material as a liberated electron which is called a photoelectron. Normally, the electron loses some amount of its energy due to the interaction with other electrons in the surroundings on its way.

The remaining energy of the electron appears as its kinetic energy. However, the energy is conserved in the process. So, the conservation of energy gives the relationship between the frequency of the incident photon and the kinetic energy of the photoelectron. This is a fundamental question in quantum mechanics, and often is called the "measurement problem".

Consider a universe consisting of only a photon flying towards an atom. If we were to run time forward until long after the photon would have reached the atom, the system will be in a superposition of states including all possible processes with the correct weighting to give the relative probabilities. It isn't until the system interacts with a larger "classical" measurement device that one of the many processes is selected "the wavefunction collapses".

According to the usual interpretation of quantum mechanics, which branch occurs is simply determined by the probability, with nothing in particular causing the selection.

Of course, there are conceptual difficulties around where the boundary between "classical" and "quantum" systems should be. You might find it interesting to read about "decoherence" as one possible mechanism for apparent wavefunction collapse. The photoelectric effect couples two electron states whose frequency difference is equal to the frequency of the incident light.

The Compton effect couples two electron states whose standing wavelength is equal to the wavelength of the incident light.

I explain how the wavelength interaction explains the Compton Effect in this blogpost. As far as i am able to comprehend your question, the answer to it lies,according me, as we all know electrons are present in atom arranged in a set of orbitals not orbits for an electron to move to the next shell or orbital ,it requires a specific amount of energy which depends upon the particular atom. All it says is dat there are certain gaps between the bands orbitals arranged together therefore u need a greater amount of energy to make it jump.

And i really apologize for my immature gesture, i will surely obey your instructions. I couldn't find a plot of anything like the process you described, but I did find this plot of Higgs decay products as a example of the probabilistic nature of quantum mechanics. On the bottom axis is the possible higgs mass now determined to be pretty close to GeV and on the vertical axis it says given the Higgs mass, how likely it will decay to those products.

Keep in mind calculating probabilities for hands dealt in a poker game is pretty much the same thing:. Sign up to join this community. The best answers are voted up and rise to the top. Stack Overflow for Teams — Collaborate and share knowledge with a private group.

Create a free Team What is Teams? Learn more. Compton scattering vs. Asked 9 years, 4 months ago. Active 5 years, 9 months ago. Viewed 33k times.